Найти область определения функции
4-9/(x+1)+1/(x-3)≥0 (4x²-8x-12-9x+27+x+1)/(x+1)(x-3)≥0 (4x²-16x+16)/(x+1)9x-3)≥0 4(x²-4x+4)/(x+1)(x-3)≥0 4(x-2)²/(x+1)(x-3)≥0 x=2 x=-1 x=3 + _ _ + --------(-1)----------[2]----------(3)--------- x∈(-∞;-1) U (3;∞) U{2}