Log0,3(2x-4)>log0,3(x+1)

Решите задачу:

$log_{0,3}(2x-4)\ \textgreater \ log_{0,3}(x+1)\\0\ \textless \ 0,3\ \textless \ 1\\\\OD3: \left \{ {{2x-4\ \textgreater \ 0} \atop {x+1\ \textgreater \ 0}} \right.=\ \textgreater \ \left \{ {{2x\ \textgreater \ 4} \atop {x\ \textgreater \ -1}} \right. =\ \textgreater \ \left \{ {{x\ \textgreater \ 2} \atop {x\ \textgreater \ -1}} \right. =\ \textgreater \ x\ \textgreater \ 2\\\\2x-4\ \textless \ x+1\\2x-x\ \textless \ 1+4\\x\ \textless \ 5\\\\x\in(2;5)$