2(5x−12)^2−10(5x−12)+12=0 помогите пж
5x-12=t 2t²-10t+12=0 D=100-4*2*12=4 t1=10+2/4=3 t2=10-2/4=8/4=2 5x-12=3 x1=3 5x-12=2 x2=14/5=2,8