Представьте в виде многочленов ДАМ 40 БАЛЛОВ! (1-3у)3= (5z-2)3= (4х-3)3= (a+2x)3= (2y-3)3= (P-3d)3= (3n-2m)3=
1) (a+2x)³ = a³+3*a²*2x+3*a*4x² +8x³ = a³ +6a²x +12ax² +8x³2) (2y-3)³ = 8y³ - 3*4y² *3 +3*2y*9 -27=8y³ -36y² +54y - 273) (p-3q)³ = p³ -3p²*3q +3p*9q² - 27q³ = p³ -9p²q +27pq² - 27q³4) (3n-2m)³ = 27n³ -3*9n²*2m+3*3n*4m² -8m³ ==27n³ -54n²m +36nm² -8m³
=1-3•(3y)^2+3•3y-(3y)^3=1-27y^2+9y-27y^3 =125z^3-3•25z^2•2+3•5z•2^2-2^3= 125z^3-150z^2+60z-8 =64x^3-3•(4x)^2•3+3•4x•9-27=64x^3-144x^2+ 108x-28 =a^3+6a^2x+12ax^2+8x^3 =p^3-9p^2•d+27pd^2-27d^3 =27n^3-27n^2•m+36nm^2-8m^3