Во вложениях 1 пример
[x²(x-3)-(x-3)]/[(x+1)(x+2)]>0 (x-3)(x²-1)/(x+1)(x+2)]>0 (x-3)(x-1)(x+1)/[(x+1)(x+2)]>0 (x-3)(x-1)/(x+2)>0,x≠-1 x=3 x=1 x=-2 _ + + _ + --------(2) ---------(-1)-----------(1)----------(3)----------- x∈(-2;-1) U (-1;1) U (3;∞)