Решите урaвнение 1)5х^2+10x=0 2)(2x-3) (x+7)=(x+4) (2x-3)-10

Question

Решите урaвнение
1)5х^2+10x=0
2)(2x-3) (x+7)=(x+4) (2x-3)-10

Answer 1

5x^2 + 10x =0    ⇒    5x(x+2) = 0   ⇒  x1 = 0;    x2 = -2

(2x-3)(x+7) = (x+4)(2x-3) - 10

(2x-3) * (x+7 - x - 4) = - 10

(2x-3) * 3 = -10

6x - 9 = -10

6x = -1

 x = -1/6