Помогите пж. срочно* (1.2х^4 - 7y^2)(1/2x^4 + 7y^2) + 0/56x^8 + 49y^4 = 2x^8

Question

Помогите пж.
срочно*
(1.2х^4 - 7y^2)(1/2x^4 + 7y^2) + 0/56x^8 + 49y^4 = 2x^8

Answer 1

(1,2x⁴-7y²)(1,2x⁴+7y²)+0,56x⁸+49y⁴=1,44x⁸-49y⁴+0,56x⁸+49y⁴≡2x⁸.