1) X^2 + 3X - 3 < X ( так как 1 = Log ( X ) числа Х
X^2 + 3X - 3 - X < 0
X^2 + 2X - 3 < 0
D = 4 - 4*1*(-3) = 16 ; V D = 4
X1 = ( - 2 + 4 ) : 2 = 1
X2 = ( - 6 ) : 2 = ( - 3 )
( X - 1 ) * ( X + 3 ) < 0
X < 1 и X < ( - 3 ) <br>Ответ ( - бесконечность ; - 3 )
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2) X^2 - X > X
X^2 - 2X > 0
X*( X - 2 )
X > 0 X > 2