Решите по действиям срочно пж(6 класс)

Решите задачу:

$(9 \frac{3}{20} - 1.24) \div 2 \frac{1}{3} - ( \frac{3}{4} + 2 \frac{5}{8} ) \div ( - 0.625) = 3 \frac{39}{100} - ( - 5 \frac{2}{5} )= 8.79\\ 1) \: \: \: 9 \frac{3}{20} - 1.24 = 9 \frac{15}{100} - 1 \frac{24}{100} = 8 - \frac{9}{100} = 7 \frac{91}{100} \\ 2) \: \: \: 7 \frac{91}{100} \div 2 \frac{1}{3} = \frac{791}{100} \div \frac{7}{3} = \frac{791 \times 3}{100 \times 7} = \frac{113 \times 3}{100} = \frac{339}{100} = 3 \frac{39}{100} \\ 3) \: \: \: \frac{3}{4} + 2 \frac{5}{8} = 2 \frac{6 + 5}{8} = 2 \frac{11}{8} = 3 \frac{3}{8} \\ 4) \: \: \: 3 \frac{3}{8} \div ( - 0.625) = \frac{27}{8} \div ( - \frac{5}{8} ) = - \frac{27 \times 8}{8 \times 5} = - \frac{27}{5} = - 5 \frac{2}{5} \\ 5) \: \: \: 3 \frac{39}{100} - ( - 5 \frac{2}{5} ) = 3.39 + 5.4 = 8.79$