Решите задачу:
∛[(5x+2)/(x+3)]=t t+1/t=13/6 6t²-13t+6=0 D=169-144=25 t1=(13-5)/12=2/3⇒∛[(5x+2)/(x+3)]=2/3 (5x+2)/(x+3)=8/27 135x+54=8x+24 135x-8x=24-50 127x=-26 x=-26/127 t2=(13+5)/12=3/2⇒∛[(5x+2)/(x+3)]=3/2 (5x+2)/(x+3)=27/8 40x+16=27x+81 40x-27x=81-16 13x=65 x=5