3х+1<_4х-56-5у>3у-2х/6+1/2>х-1/3

Question

3х+1<_4х-5<br>6-5у>3у-2
х/6+1/2>х-1/3

Answer 1

3х+1<_4х-5<br>3х-4х<= -5-1<br>-x<= -6<br>x>=6 
x є [6; ∞)

6-5у>3у-2
-5y-3y>-2-6
-8y>-8
y<1<br>y є (-∞;1)

х/6+1/2>х-1/3
x/6-x>-1/3-1/2
x-6x>-2-3
-5x>-5
x<1<br>x є (-∞;1)