Выполните действия 3х-у х^2-6ху/9у^2 -------- *----------------- х+3у 9х^2-у^2

Решите задачу:

$\frac{3x - y}{x + 3y} \times \frac{ \frac{ {x}^{2} - 6xy }{9 {y}^{2} } }{9 {x}^{2} - {y}^{2} } = \frac{(3x - y) \times \frac{x(x - 6y)}{9 {y}^{2} } }{(x + 3y)(3x - y)(3x + y)} = \frac{ \frac{x(x - 6y)}{9 {y}^{2} } }{3 {x}^{2} + xy + 9xy + 3 {y}^{2} } = \frac{x(x - 6y)}{9 {y}^{2} (3 {x}^{2} + 10xy + 3 {y}^{2} )} = \frac{x(x - 6y)}{27 {x}^{2} {y}^{2} + 90x {y}^{3} + 27 {y}^{4} }$