(2x+5)^2+(5x-3)^2=75+2x найти корни
4х²+20х+25+25х²-30х+9=75+2х 4х²+20х+25+25х²-30х+9-75-2х=0 29х²-12х-41=0 D=12² - 4×29×(-41)=4900=70² x1=12+70/58=82/58=1 целая 12/29 x2=12-70/58=-1 Ответ: (-1; 1 целая 12/29)