12/x-√x-(x-6)^2 найти производную

Решите задачу:

$\frac{d}{dx} [ \frac{12}{x}- \sqrt{x} -((x-6)(x-6))]$
$\frac{d}{dx}[ \frac{12}{x} - \sqrt{x} -(xx+x*-6-6x-6*-6)]$
$\frac{d}{dx} [ \frac{12}{x}- \sqrt{x} -(x^2-12x+36)]$
$\frac{d}{dx} [ \frac{12}{x} ]+ \frac{d}{dx}[- \sqrt{x} ]+ \frac{d}{dx}[-(x^2-12x+36)]$
$-12x^{-2}+ \frac{d}{dx}[- \sqrt{x} ]+ \frac{d}{dx}[-(x^2-12x+36)]$
$-12x^{-2}- \frac{x^{ \frac{1}{2} }}{2} + \frac{d}{dx} [-(x^2-12x+36)]$
$-12x^{-2}- \frac{x^-{ \frac{1}{2} }}{2} -(2x-12)$
$-12 \frac{1}{x^2} - \frac{x^{- \frac{1}{2}} }{2} -(2x-12)$
$-12 \frac{1}{x^2} - \frac{ \frac{1}{x^{ \frac{1}{2}} } }{2} -(2x-12)$
$-2x+12- \frac{12}{x^2} - \frac{1}{2x^{ \frac{1}{2}} }$