Решите неравенства помогите пожалуйста Срочно

Решите задачу:

$3-x \geq 3x+5 \\ -4x \geq 2 \\ x \leq - \frac{1}{2} \\ ----------------------- \\ x+6x-1\ \textless \ 0 \\ 7x\ \textless \ 1 \\ x\ \textless \ \frac{1}{7} \\ ----------------------- \\ 2x- x^{2} \leq 0 \\ x(2-x) \leq 0 \\ x \leq 4;x \geq 4 \\ ----------------------- \\ x^{2} +5x+6\ \textgreater \ 0 \\ x _{1} =-3; x _{2} =-2 \\ x\ \textless \ -3;x\ \textgreater \ -2 \\ \\ ------------------------ \\ \left \{ {{x\ \textgreater \ -1} \atop {3-x\ \textgreater \ 0}} \right. \left \{ {{x\ \textgreater \ -1} \atop {x\ \textless \ 3}} \right. \\ ------------------------ \\ \left \{ {{-48+6x\ \textgreater \ 0} \atop {6-5x\ \textgreater \ -4}} \right. \\ x\ \textgreater \ 6; x\ \textless \ 2$