Решите под буквой (а , СРОЧНО!

$\left \{ {{4-3x \leq 1} \atop { \frac{x}{2} \geq -1 }} \right.$

$\left \{ {{-3x \leq 1-4} \atop { x \geq -2 }} \right.$

$\left \{ {{-3x \leq -3} \atop { x \geq -2 }} \right.$

$\left \{ {{x \geq 1} \atop { x \geq -2 }} \right.$

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Ответ: $[1;+$ ∞ $)$