5-10+19*5/3+75-106+1

Решите задачу:

$1) 19 \times \frac{5}{3} = \frac{95}{3} \\ 2)5 - 10 = - 5 \\ 3) - 5 \times 3 + \frac{95}{3} = - \frac{15}{3} + \frac{95}{3} = \frac{80}{3} \\ 4) \frac{80}{3} + 75 \times 3 = \frac{80}{3} + \frac{225}{3} = \frac{305}{3} \\ 5) \frac{305}{3} - 106 \times 3 = \frac{305}{3} - \frac{318}{3} = \frac{ - 13}{3} \\ 6) \frac{ - 13}{3} + 1 \times 3 = \frac{ - 13}{3} + \frac{3}{3} = \frac{ - 10}{3} = - 3 \times \frac{1}{3}$