Дано
a) m(FeS) = 60 g
b) m(CuS) = 19.2 g
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V(SO2)-?
60 X
4FeS+7O2-->2Fe2O3+4SO2 M(FeS) = 88 g/mol , Vm=22.4 L/mol
4*88 4*22.4
X = 60*4*22.4 / 352 = 15.27 L
19.2 X
2CuS+3O2-->2CuO+2SO2 M(CuS)=96 g/mol , Vm=22.4 L/mol
2*96 2*22.4
X = 19.2*2*22.4 / 192 = 4.48 L
ответ 15.27 л , 4.48 л