(b^2-b^2)(b^3+b^2)-(1+b^2)(1-b^2+b^4 b= 0.1

Question

(b^2-b^2)(b^3+b^2)-(1+b^2)(1-b^2+b^4 b= 0.1

Answer 1

-(b^2 +1)(b^4 -b^2 +1)b+0(b^3 +b^2=1/10
b(-b^6 +b^4 -b^2 *1-1b^4 +1b^2 -1)=1/10
b(-b^6 -b^4 +b^4 -b^2 +b^2 -1)=1/10
b(-b^6 -1)=1/10
-b^7 -b*1=1/10
-b^7 - b =1/10

Comments

спасибо