Помогите решить уравнения 3 1/12- 1 5/6 у =1 17/22 (7/12 +11/30х):7 1/4=1/5

▪

$3 \frac{1}{12} - 1 \frac{5}{6} y = 1 \frac{17}{22} \\ 3 \frac{1}{12 } - 1 \frac{17}{22} = 1 \frac{5}{6} y \\ 1 \frac{5}{6} y = 2 \frac{11 - 17 \times 6}{132} = 2 \frac{11 - 102}{132} = 2 - \frac{91}{132} = 1 \frac{132 - 91}{132} = 1 \frac{41}{132} \\ 1 \frac{5}{6} y = 1 \frac{41}{132} \\ y = 1 \frac{41}{132} \div 1 \frac{5}{6} = \frac{173 \times 6}{132 \times 11} = \frac{173}{22 \times 11} = \frac{173}{242} \\ y = \frac{173}{242}$

▪

$( \frac{7}{12} + \frac{11}{30} x) \div 7 \frac{1}{4} = \frac{1}{5} \\ \frac{7}{12} + \frac{11}{30} x = \frac{1}{5} \times \frac{29}{4} \\ \frac{7}{12} + \frac{11}{30} x = \frac{29}{20} \\ \frac{11}{30} x = 1 \frac{9}{20} - \frac{7}{12} = 1 \frac{9 \times 3 - 7 \times5 }{60} = 1 \frac{27 - 35}{60} = 1 - \frac{8}{60} = 1 - \frac{2}{15} = \frac{13}{15 } \\ \frac{11}{30} x = \frac{13}{15} \\ x = \frac{13}{15} \div \frac{11}{30} = \frac{13 \times 30}{15 \times 11} = \frac{13 \times 2}{11} = \frac{26}{11} \\ x = 2 \frac{4}{11}$

________________

решение верное не сомневайся, т.к. я сделала проверку вычисленных корней уравнения.