Log2(4x-5)=log2(3x+4)+1

Question

Log2(4x-5)=log2(3x+4)+1

Answer 1

Вот решение)
Не благодарите

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Answer 2

Log2(4x-5)=log2(3x+4)+1
log2(4x-5)-log2(3x+4)=1
4x-5/3x+4=2^1
4x-5=2(3x+4)
4x-5=6x+8
4x-5-6x-8=0
-2x-13=0
-2x=13
x=-13/2
x=-6,5