Помогите с решением log8 (2x-7)< 1

$log_8(2x-7)\ \textless \ 1\\\\ \left \{ {{log_8(2x-7)\ \textless \ 1} \atop {2x-7\ \textgreater \ 0}} \right. \\\\ \left \{ {{log_8(2x-7)\ \textless \ log_8 8} \atop {2x\ \textgreater \ 7}} \right. \\\\ \left \{ {{2x-7\ \textless \ 8} \atop {x\ \textgreater \ 3.5}} \right. \\\\ \left \{ {{2x\ \textless \ 15} \atop {x\ \textgreater \ 3.5}} \right. \\\\ \left \{ {{2x\ \textless \ 15} \atop {x\ \textgreater \ 3.5}} \right. \\\\ \left \{ {{x\ \textless \ 7.5} \atop {x\ \textgreater \ 3.5}} \right. \\$

Ответ: $x \in (3.5;7.5)$