(m-1)^2+(m+1)^2>=2(m-1)(m+1)
(m-1)^2+(m+1)^2>=2(m-1)(m+1) =2m^2-2" alt="m^2-2m+1+m^2+2m+1>=2m^2-2" align="absmiddle" class="latex-formula"> 2>=-2 Ответ: m-любое число
![(m-1)^2+(m+1)^2 \geq 2(m-1)(m+1)
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m^2-2m+1+m^2+2m+1 \geq 2(m^2-1)
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2m^2+2 \geq 2m^2-2
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2 \geq -2](https://tex.z-dn.net/?f=%28m-1%29%5E2%2B%28m%2B1%29%5E2+%5Cgeq+2%28m-1%29%28m%2B1%29%0A%5C%5C%5C%0Am%5E2-2m%2B1%2Bm%5E2%2B2m%2B1+%5Cgeq+2%28m%5E2-1%29%0A%5C%5C%5C%0A2m%5E2%2B2+%5Cgeq+2m%5E2-2%0A%5C%5C%5C%0A2+%5Cgeq+-2 "(m-1)^2+(m+1)^2 \geq 2(m-1)(m+1)
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m^2-2m+1+m^2+2m+1 \geq 2(m^2-1)
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2m^2+2 \geq 2m^2-2
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2 \geq -2")