Решите уравнение: 2^(8-х^2)=4^х
2^(8-x^2) = 4^x 2^(8-x^2)= 2^(2x) 8-x^2 = 2x 8-x^2 - 2x = 0 -x^2 - 2x +8 = 0 x^2 + 2x - 8 =0 D=4+32 = 36=6^2 x1=-2+6 / 2 = 2 x2=-2-6/2 = -4 Ответ : x1=2 , x2 = -4