Решите плиз номера под 4,5,6 номерами кроме последнего варианта

Question 1

Question 2

Решите задачу:

$( \sqrt{7} - \sqrt{3})^2=7-2 \sqrt{21}+3=10-2 \sqrt{21} \\ (5+ \sqrt{3})^2 =25+10 \sqrt{3}+3=28+10 \sqrt{3} \\ (5- \sqrt{3})^2 =25-10 \sqrt{3}+3=28-10 \sqrt{3} \\ ( \sqrt{5}+\sqrt{3})^2 =5+2\sqrt{15}+3=8+2\sqrt{15} \\ ( \sqrt{5}-\sqrt{3})^2 =5-2\sqrt{15}+3=8-2\sqrt{15} \\ 0,5 \sqrt{0,01}- \frac{1}{26} *\sqrt{169}= \frac{1}{2}*\frac{1}{10}-\frac{1}{2} =\frac{1}{20}-\frac{1}{2} =-\frac{9}{20} \\ 7 \sqrt{0,04}+\frac{1}{6} \sqrt{144}=7\frac{1}{5}+2=\frac{7}{5}+2=3,4 \\$
$7 \sqrt{0,04}-\frac{1}{6} \sqrt{144}=7 \sqrt{ \frac{1}{25} } -\frac{1}{6}*12=\frac{7}{5}-2=-0,6 \\ 0,5 \sqrt{0,04} +\frac{1}{16} \sqrt{100} =\frac{1}{2}*\frac{1}{5}+\frac{1}{8}*5=\frac{29}{40}=0,725 \\ 5 \sqrt{0,04}- \frac{1}{16} \sqrt{100}=5*\frac{1}{5}-\frac{1}{8}*5=\frac{3}{8}=0,375 \\ 2\sqrt{2}+2\sqrt{50}-2\sqrt{32}=2\sqrt{2}+10\sqrt{2}-8\sqrt{2}=4\sqrt{2} \\ 7\sqrt{2}-2\sqrt{50}+2\sqrt{32}=7\sqrt{2}-10\sqrt{2}+8\sqrt{2}=5\sqrt{2} \\$
$12\sqrt{2}+6\sqrt{50}-3\sqrt{32}= 12\sqrt{2}+30\sqrt{2}-12\sqrt{2}=30\sqrt{2} \\ 10\sqrt{2}-3\sqrt{50}-2\sqrt{32}=10\sqrt{2}-15\sqrt{2} -8\sqrt{2}=-13\sqrt{2} \\ 8\sqrt{2}-3\sqrt{50}+2\sqrt{32}=8\sqrt{2}-15\sqrt{2}+8\sqrt{2}=\sqrt{2}$