1, 2 и 3 СРОЧНО!!!!!!

1. $\frac{ 2x^{2} -5x+3}{x-1} = \frac{(x-1)(x-1.5)}{x-1}=x-1.5$
3. a)6x-0.5(4x-3) " alt="2x-4.5>6x-0.5(4x-3) " align="absmiddle" class="latex-formula">
1.5+4.5" alt="2x-6x+2x>1.5+4.5" align="absmiddle" class="latex-formula">
6" alt="-2x>6" align="absmiddle" class="latex-formula">
-3" alt="x>-3" align="absmiddle" class="latex-formula">
x∈(-3;+бесконечности)
б) $x^{2} \geq 16$
x1=4 x2=-4
x∈(-беск;-4][4;+беск)
в) 0" alt="2 x^{2} -x-15>0" align="absmiddle" class="latex-formula">
  0" alt="(x-3)(x+2.5)>0" align="absmiddle" class="latex-formula">
x=3 x=-2.5
  x∈(-беск;-2.5)(3;+беск)
г) $\frac{3+x}{8-x} \geq 0$
   $(3+x) \geq (8-x)$
   $x \geq 2.5$
x∈[2.5;8)(8;+бекс)