Вычислите: а) √324; √3,61; √81/196; √1 64/225. решите уравнение x^2=169 x^2=13 √x=13

$\sqrt{324} = 18$
$\sqrt{3,61}= 1,9$
$\sqrt{ \frac{81}{196} }= \frac{9}{14}$
$\sqrt{1 \frac{64}{225} }= \sqrt{ \frac{289}{225} } = \frac{17}{15}= 1 \frac{2}{15}$

$x^{2} = 169$
$X _{1} = 13$ $X _{2} = - 13$

$x^{2} = 13$
$X _{1} = \sqrt{13}$ $X _{2} = - \sqrt{13}$

$\sqrt{x}= 13$
X = 169