(4+2х)(5+2Х)=56 помогите решить уравнение
Начинаю
(4 + 2x)(5 + 2x) = 56 20 + 10x + 8x + 4x² - 56 = 0 2x² + 9x - 18 = 0 D = b²-4ac = 81+144 = 225 = 15² x₁ = (-b+√D)/2a = (-9+15)/4 = 1,5 x₂ = (-b -√D)/2a = (-9-15)/4 = -6 Ответ: {1,5; -6}
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