Log(2)56=log(2)7*8=log(2)7+3 log(28)2=log(2)2/log(2)7*4=1/log(2)7+2 log(224)2=log(2)2/log(2)7*32=1/log(2)7+5 Получаем (log(2)7+3)(log(2)7+2)-log(2)7(log(2)7+5)=6+5log(2)7+log²(2)7-log²(2)7-5log(2)7=6