Решите уравнение формулой Крамра 3x+4y=253 y-5x=0

Решите задачу:

$\left \{ {{3x+4y=253} \atop {-5x+y=0}} \right. \\\\\\\Delta = \left|\begin{array}{cc}3&4\\-5&1\end{array}\right|=3\cdot 1-4\cdot (-5)=3+20=23\ne 0\\\\\\\Delta _1= \left|\begin{array}{cc}253&0\\4&1\end{array}\right|=253\\\\\\\Delta _2= \left|\begin{array}{cc}3&-5\\253&0\end{array}\right|=3\\\\\\x= \frac{\Delta _1}{\Delta }= \frac{253}{23}=11\\\\\\y= \frac{\Delta _2}{\Delta }=\frac{3}{23}$