ХЕЛПППП ♡решите систему неравенств

$\left \{ {{12 - 5x \ \textless \ 3(x-4)} \atop {4x - 2 \ \textgreater \ 2(3-x)}} \right.$
$\left \{ {{12 - 5x \ \textless \ 3x - 12} \atop {4x - 2 \ \textgreater \ 6 - 2x}} \right.$
$\left \{ {{8x \ \textgreater \ 24} \atop {6x \ \textgreater \ 8}} \right.$
$\left \{ {{x \ \textgreater \ 3} \atop {x \ \textgreater \ \frac{8}{6} = \frac{4}{3} = 1\frac{1}{3} }} \right.$

———○——○——>x
$1\frac{1}{3}$ 3
⇒ x > 3

Ответ: x ∈ (3; +∞)