For a positive integer n, we define a function f: f (n) = - 1 + 2 - 3 + .. + (- 1) nn...

Question

For a positive integer n, we define a function f:

f (n) = - 1 + 2 - 3 + .. + (- 1) nn

Your task is to calculate f (n) for a given integer n.

Input data
The only line contains a positive integer n (1 ≤ n ≤ 1015).

Output
Output f (n) in a single line.
with c++

Answer 1

#include
using namespace std;
int main()
{
int n = 0, f = 0, t = 0;
cin >> n;
if (n <= 1015 && n >= 1) {
for (int i = 1; i <= n; ++i) {<br>    t = -i;
if (i % 2 == 0) {
t = abs(t);
}
cout << t << " ";<br>f += t;
}
} else {
cout << "Error" << endl;<br>}
cout << endl << "Res: " << f;<br>return 0;
}