(2x-1)^2 + (2x+1)*(2x-1)
4x^2 - 4x + 1 + 4x^2 - 1
8x^2 - 4x = 0
4x(2x-1) = 0
4x = 0 и 2x - 1 = 0
x = 0 и 2x = 1
x = 1/2
Или же, если (2x-1)*2
(2x-1)2 + (2x+1)*(2x-1)
4x - 2 + 4x^2 - 1
4x^2 + 4x - 3 = 0
4x^2/4 + 4x - 3*4 = 0
x -> a
a^2 + 4a - 12 = 0
a1 = -6
a2 = 2
x1 = -6/4 = -3/2
x2 = 2/6 = 1/3