Помогите пожалуйста решить 98 (1)

$\left \{ {{xy=36} \atop { \sqrt{x} + \sqrt{y}=5 }} \right. \\ \left \{ {{x= \frac{36}{y} } \atop { \sqrt{ \frac{36}{y}}+ \sqrt{y}=5 * } } \right. \\ * \sqrt{ \frac{36}{y}}+ \sqrt{y}=5 \\ 6+y-5 \sqrt{y} =0$
Пусть $\sqrt{y}$ = t, t≥0
$t^2-5t+6=0 \\ t1=2 \\ t2=3$
1) $\sqrt{y}=2 \\ y=4 \\ \left \{ {{y=4} \atop {x= \frac{36}{y} }} \right. \\ \left \{ {{y=4} \atop {x= \frac{36}{4} }} \right. \\ \left \{ {{y=4} \atop {x=9} }} \right.$
2) $\sqrt{y} =3 \\ y=9 \\ \left \{ {{y=9} \atop {x= \frac{36}{x} }} \right. \\ \left \{ {{y=9} \atop {x= \frac{36}{9} }} \right. \\ \left \{ {{y=9} \atop {x= 4 }} \right.$