Хто сможет решить??????

1) $2 ^{x}*3 ^{x+1} =108$
$2 ^{x}*3 ^{x+1}= 2 ^{2} *3 ^{3}$
x = 2 x+1 = 3
x = 2
2) $(\frac{1}{2}) ^{ x^{2} -x} = \sqrt[4]{2}$
$2 ^{x - x^{2} } = 2 ^{ \frac{1}{4} }$
x - x² = 1/4
x² - x + 0,25 = 0
D = 1 - 4*0,25= 1-1= 0
x = 0,5
3) $( \frac{2}{3}) ^{x} * ( \frac{9}{8}) ^{x} = \frac{27}{64}$
$( \frac{2}{3} * \frac{9}{8}) ^{x} = \frac{27}{64}$
$( \frac{3}{4}) ^{x} = ( \frac{3}{4} ) ^{3}$
$x = 3$