)))))))))))))))))помогите

Решите задачу:

$1) \frac{x+9}{7} = 1+\frac{x+1}{3};\\ \frac{3(x+9)}{21} = \frac{21+7(x+1)}{21};\\ 3x+27=21+7x+1;\\ 3x - 7x = 21 + 1 -27;\\ -4x=1 | : (-1)\\ x = - \frac{1}{4}; \\\\ 2) 1-\frac{5x-2}{6}=\frac{x-5}{9};\\ \frac{18-3(5x-2)}{18} = \frac{2(x-5}{18};\\ 18-15x+6=2x-10;\\-15x-2x=-10-18-6;\\17x = -34 | : (-17)\\ x = 2;\\\\ 3) \frac{3x+4}{5} + \frac{x-7}{2} = \frac{2(2x+3)}{5};\\ \frac{3x+4}{5} + \frac{x-7}{2} = \frac{4x+6}{5};\\ 6x+8+5x-35=8x+12;\\ 11x-27=8x+12;\\ 11x-8x=12+27;\\ 3x = 39 | : 3\\ x=13;$