ПОМОГИИИИТЕ! ЗАДАНИЕ ВО ВЛОЖЕНИЯХ

Question

ПОМОГИИИИТЕ! ЗАДАНИЕ ВО ВЛОЖЕНИЯХ

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Answer 1

[tex] \frac{ x^{3} y+2 x^{2} y-3xy}{ x^{3} +5 x^{2} +6x} : \frac{1- x^{2} }{ x^{2} +3x+2} = \frac{xy*(x+3)*(x-1)}{x*(x+2)*(x+3)} * \frac{(x+2)*(x+1)}{(1-x)*(1+x)}= \frac{y*(x-1)}{1-x} = -y*(1-x)/(1-x)=-y