ООООЧЕНЬ СРОЧНО! !!!! РЕБЯТА, ПОМОГИТЕ)

Решите задачу:

$a)-3^{-4} \ \textless \ (-3)^{-4} \\\\ -3^{-4} = -\frac{1}{3^{4}}\\\\ (-3)^{-4} = \frac{1}{(-3)^{4}} = \frac{1}{3^{4}}$

$b)-5^{-3}=(-5)^{-3} \\\\ -5^{-3} = -\frac{1}{5^{3}}\\\\ (-5)^{-3} = \frac{1}{(-5)^{3}} = -\frac{1}{5^{3}}$

$v)-(-1)^{-3}=(-1)^{-2} \\\\ -(-1)^{-3} = -\frac{1}{(-1)^{3}} = \frac{1}{1^{3}} = 1\\\\ (-1)^{-2} = \frac{1}{(-1)^{2}} = 1\\$

$g)-5^{0} \ \textless \ (-5)^{0} \\\\ -5^{0} = -1\\\\ (-5)^{0} = 1\\$