15*(3а-4в)= 6*(2а+5с)= 11*(а-в*в+3в)= (7а-в)*13= 15*x:3у= 7x*5у*а= 4а*7*2в*с=

Question

15*(3а-4в)=

6*(2а+5с)=

11*(а-в*в+3в)=

(7а-в)*13=

15*x:3у=

7x*5у*а=

4а*7*2в*с=

Answer 1

15*(3а-4б)=15*3а-15*4б=45а-60б (2а+5с)=6*2а+6*5с=12а+30с 11(а-в2+3в). 11а-11в2+33в 75аху 35аху 56авс

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Answer 2

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