Нужно сократить, вторую, 3 , 5
3) (b-7)(b+7)/(7-b)^2 = - (7-b)(b+7)/(7-b)^2= -(b+7)/(7-b) = (b+7)/(b-7) 5) 3b(b+3)/(b-3)(b+3) = 3b/(b-3)