Сократить дроби. Пожалуйста помогите)) Заранее спасибо ❤

Решите задачу:

$\frac{14b^3}{21b} = \frac{2b^2}{3}$

$\frac{x^2 - 9}{3x - 9} = \frac{(x-3)(x+3)}{3(x-3)} = \frac{(x+3)}{3}$

$\frac{5y - 10y^2}{2y - 1} = \frac{5y(1 - 2y)}{-(1 - 2y)} = -5y$

$\frac{4x - 16}{x^2 - 16} = \frac{4(x-4)}{(x-4)(x+4)} = \frac{4}{x+4}$

$\frac{12y^3 - 8y^2}{2 - 3y} = \frac{4y^2(3y - 2)}{-(3y - 2)} = -4y^2$

$\frac{2b+18}{b^2 + 18b + 81} = \frac{2(b+9)}{(b+9)^2} = \frac{2}{b+9}$

$\frac{15x^2y^6}{9x^3y^4} = \frac{5y^2}{3x}$

$\frac{b^2 + 10b + 25}{5b + 25} = \frac{(b+5)^2}{5(b+5)} = \frac{(b+5)}{5}$

$\frac{4 - y^2}{y^2 - 4y + 4} = \frac{-(y^2 - 4)}{(y - 2)^2} = \frac{-((y-2)(y+2))}{(y - 2)^2} = \frac{-y-2}{(y - 2)} =$