Tg13π/6-sin(-5π/3) Решите пожалуйста

Question

Tg13π/6-sin(-5π/3)
Решите пожалуйста

Answer 1

Tg13π/6-sin(-5π/3)=tg(2π+π/6)+sin (5π/3)=tg(π/6)+sin(6π/3-π/3)=
=(√3)/3+sin(2π-π/3)=(√3)/3+sin(-π/3)=(√3)/3-(√3)/2=-(√3)/6

Comments

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