1) 1/(x^2 +2x +1) - 1/(1-x^2) = (1-x^2 - x^2 -2x -1) / (x+1)^2 *(1-x^2) = (-2x^2 -2x)/(x+1)^2 * (1-x)*(1+x) = -2x*(x+1)/(x+1)^2*(1-x)*(1+x) = -2x/(x+1)^2*(x-1)
2) 2x/(x^2-1) : (-2x)/(x+1)^2*(x-1) = 2x/(x-1)*(x+1) * (x+1)^2*(x-1)/(-2x) = -1/(x+1)
Ответ: -1/(х+1)