(6x+3) в квадрате=(x-4)в квадрате
(6x + 3)^2 - (x - 4)^2 = 0 (6x + 3 - x + 4)(6x + 3 + x - 4) = 0 (5x + 7)(7x - 1) =0 5x + 7 = 0 5x = - 7 x = - 1,4 7x - 1 = 0 7x = 1 x = 1/7