Помогите решить тригонометрическое уравнение.
√3·tg(3x + π/6) = 3 tg(3x + π/6) = √3 3x + π/6 =π/3 + πn, n ∈ Z 3x = π/3 - π/6 + πn, n ∈ Z 3x = π/6 + πn, n ∈ Z x = π/18 + πn/3, n ∈ Z
√3tg(3x+π/6)=3 tg(3x+π/6)=√3 3x+π/6=π/3+πk 3x=π/6+πk x=π/18+πk/3,k∈z