{2x-6 > 0
{x²+8x+7 ≥ 0
1) 2х-6 > 0
2х > 6
x > 3
3 //////////////
---------------₀------------->x
х∈(3; ∞)
2) x²+8x+7 ≥ 0
D = 64-28 = 36
x₁,₂ = (-8⁺₋6)/2 = -1; -7
+ - +
-----------.-----------.----------->x
\\\\\\\\\\\ -7 -1 \\\\\\\\\\\\\\\
x∈(-∞; -7]∪[-1; ∞)
3)
3///////////
-------.----------.--------------₀-------->x
\\\\\\\-7 -1\\\\\\\\\\\\\\\\\\\\\\\\\\\\
x∈(3; ∞)