(3 - х² )² - (5 - х² )² = 0 Помогите
(3 - x^2 - 5 + x^2)(3 - x^2 + 5 - x^2) = 0 - 2 (- 2x^2 + 8) = 0 /: - 2 - 2x^2 + 8 = 0 /: - 2 x^2 - 4 = 0 x^2 = 4 x = ± √4 x = ± 2