1
4x³-14x²-5x-12 |x-4
4x³-16x² 4x²+2x+3
----------------
2x²-5x
2x²-8x
-------------------
3x-12
3x-12
----------------
0
Ответ 5
2
ОДЗ
{x>0
{14x-3>0⇒14x>3⇒x>3/14
x∈(3/14;∞)
log(2)8+log(2)x²=log(2)(14x-3)
log(2)(8x²)=log(2)(14x-3)
8x²=14x-3
8x²-14x+3=0
D=196-96=100
x1=(14-10)/16=1/4
x2=(14+10)/16=1,5
Ответ 2