Решите систему неравенств.

$\left \{ {{x^2-3x-4\ \textless \ 0} \atop {3x-12\ \textgreater \ 0}} \right. \\ x^2+x-4x-4\ \textless \ 0 \\ x(x+1)-4(x+1)\ \textless \ 0 \\ (x-4)(x+1)\ \textless \ 0 \\$
ОДЗ
$\left \{ {{x-4\ \textless \ 0} \atop {x+1\ \textgreater \ 0}} \right. \\ \left \{ {{x-4\ \textgreater \ 0} \atop {x+1\ \textless \ )}} \right. \\ \left \{ {{x\ \textless \ 4} \atop {x\ \textgreater \ -1}} \right. \\ \left \{ {{x\ \textgreater \ 4} \atop {x\ \textless \ -1}} \right. \\$
x∈(-1;4)
x∈∅
x∈(-1;4)