ОДЗ
{x>0
{log(2)x+1≠0⇒log(2)x≠-1⇒x≠1/2
x∈(0;0,5) U (0,5;∞)
4/(log(2)x+1)-1≤0
(4-log(2)x -1)/(log(2x+1)≤0
(3-log(2)x)/(log(2)x+1)≤0
1){3-log(2)x≤0⇒log(2)x≥3⇒x≥8
{log(2)x+1>0⇒log(2)x>-1⇒x>0,5
x≥8
2){3-log(2)x≥0⇒log(2)x≤3⇒x≤8
{log(2)x+1<0⇒log(2)x<-1⇒x<0,5<br>x<0,5 +ОДЗ⇒0<x<0,5<br>Ответ x∈(0;0,5) U [8;∞)